nco2=22,4:1,12=0,05 mol
a) Co2 +Ca(OH)2-----> CaCo3+H2O
0,05......0,05....................0,05.....0,05
b) CM=nCa(OH)2\Vdd=0,05\0,05=1M
mCaCO3=0,05.100=5 g
\(n_{CO2}=\frac{1,12}{22,4}=0,05\left(mol\right)\)
Đổi 100ml = 0,1ml
\(PTHH:Ca\left(OH\right)_2+CO_2\rightarrow CaCO_3+H_2O\)
______0,05___________0,05______0,05_______
\(\Rightarrow m_{CaCO3}=0,05.100=5\left(g\right)\)
\(\Rightarrow CM_{Ca\left(OH\right)2}=\frac{0,05}{0,1}=0,5M\)