b: \(\dfrac{3x}{5}=\dfrac{y}{4}\)
nên \(\dfrac{x}{\dfrac{5}{3}}=\dfrac{y}{4}\)
=>x/5=y/12
Đặt x/5=y/12=k
=>x=5k; y=12k
Ta có: xy=180
=>60k^2=180
=>k^2=3
TH1: \(k=\sqrt{3}\)
=>\(x=5\sqrt{3};y=12\sqrt{3}\)
TH2: \(k=-\sqrt{3}\)
=>\(x=-5\sqrt{3};y=-12\sqrt{3}\)