Question

Có bao nhiêu nguyên tử trong 25 gam muối CuSO5.5H2O giúp e vs ạ

Answer 1

\(n_{CuSO_4.5H_2O}=\dfrac{25}{250}=0,1\left(mol\right)\\ \Rightarrow n_{CuSO_4}=0,1\left(mol\right)\\ n_{H_2O}=5.0,1=0,5\left(mol\right)\\ n_{ng.tử}=n_{Cu}=n_S+n_H+n_{O\left(tổng\right)}=0,1+0,1+2.5.0,1+\left(4.0,1+0,1.5\right)=2,1\left(mol\right)\\ Số.nguyên.tử:2,1.6,023.10^{23}=12.6483.10^{23}\left(ng.tử\right)\)