\(0,\left(37\right)+0,\left(62\right)=0,\left(99\right)\)
Theo quy ước làm tròn số ta dược :
\(0,\left(99\right)\approx1\) (đpcm)
b) Làm tương tự câu a) ta có :
\(0,\left(33\right).3=0,\left(99\right)\approx1\) (đpcm)
ta có:0,(37)=1/99*37=37/99
0,(62)=1/99*62=62/99
0,(37)+0,(62)=37/99+62/99=99/99=1(đpcm)
a) Ta có:
\(0,\left(37\right)+0,\left(62\right)=0,\left(01\right)\cdot37+0,\left(01\right)\cdot62=\frac{1}{99}\cdot37+\frac{1}{99}\cdot62\)
\(=\frac{37}{99}+\frac{62}{99}=1\) (đpcm)
b) Ta có:
\(0,\left(33\right)\cdot3=0,\left(01\right)\cdot33\cdot3=\frac{1}{99}\cdot99=1\) (đpcm)
