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Biến đổi VT ta có:
VT= \(\left(\dfrac{x^2-3xy}{x+y}+y\right):\left(\dfrac{x}{x+y}-\dfrac{y}{y-x}-\dfrac{2xy}{x^2-y^2}\right)\)
= \(\left(\dfrac{x^2-3xy+xy+y^2}{x+y}\right):\left(\dfrac{x}{x+y}+\dfrac{y}{x-y}-\dfrac{2xy}{\left(x-y\right)\left(x+y\right)}\right)\)
= \(\left(\dfrac{x^2-2xy+y^2}{x+y}\right):\left(\dfrac{x^2-xy+xy+y^2-2xy}{\left(x-y\right)\left(x+y\right)}\right)\)
= \(\dfrac{\left(x-y\right)^2}{x+y}:\left(\dfrac{\left(x-y\right)^2}{\left(x-y\right)\left(x+y\right)}\right)\)
= \(\dfrac{\left(x-y\right)^2}{x+y}.\dfrac{x+y}{x-y}\) = x - y = VP
Vậy...