\(tan\alpha+\frac{cos\alpha}{1+sin\alpha}=\frac{sin\alpha}{cos\alpha}+\frac{cos\alpha}{1+sin\alpha}=\frac{sin^2\alpha+sin\alpha+cos^2\alpha}{cos\alpha\left(1+sin\alpha\right)}=\frac{1+sin\alpha}{cos\alpha\left(1+sin\alpha\right)}=\frac{1}{cos\alpha}\)=>đpcm