Sửa đề: \(A=\left(\dfrac{x+y}{2x-2y}-\dfrac{x-y}{2x+2y}-\dfrac{2y^2}{y^2-x^2}\right):\dfrac{2y}{x-y}\)
Ta có: \(A=\left(\dfrac{x+y}{2x-2y}-\dfrac{x-y}{2x+2y}-\dfrac{2y^2}{y^2-x^2}\right):\dfrac{2y}{x-y}\)
\(=\left(\dfrac{x+y}{2\left(x-y\right)}-\dfrac{x-y}{2\left(x+y\right)}+\dfrac{2y^2}{\left(x-y\right)\left(x+y\right)}\right):\dfrac{2y}{x-y}\)
\(=\left(\dfrac{\left(x+y\right)^2}{2\left(x-y\right)\left(x+y\right)}-\dfrac{\left(x-y\right)^2}{2\left(x+y\right)\left(x-y\right)}+\dfrac{4y^2}{2\left(x-y\right)\left(x+y\right)}\right):\dfrac{2y}{x-y}\)
\(=\left(\dfrac{x^2+2xy+y^2-x^2+2xy-y^2+4y^2}{2\left(x-y\right)\left(x+y\right)}\right):\dfrac{2y}{x-y}\)
\(=\dfrac{4y^2+4xy}{2\left(x-y\right)\left(x+y\right)}:\dfrac{2y}{x-y}\)
\(=\dfrac{4y\left(y+x\right)}{2\left(x-y\right)\left(y+x\right)}\cdot\dfrac{x-y}{2y}\)
\(=1\)
