Question

cho x:z=\(\dfrac{2}{3}:\dfrac{1}{2};z:y=1:\dfrac{4}{7}\)và y+z=66. Khi đó x+y+z=..........................

Answer 1

Ta có :

\(\dfrac{x}{\dfrac{2}{3}}=\dfrac{z}{0,5};\dfrac{z}{1}=\dfrac{y}{\dfrac{4}{7}}\)

\(\Leftrightarrow\)\(\dfrac{x}{\dfrac{16}{3}}=\dfrac{z}{4}=\dfrac{y}{\dfrac{16}{7}}\)

\(\Rightarrow\)\(\dfrac{z+y}{4+\dfrac{16}{7}}=\dfrac{66}{\dfrac{44}{7}}=10,5\)

[ \(\dfrac{z}{4}=10,5\Rightarrow z=42\) ]

[ \(\dfrac{y}{\dfrac{16}{7}}=10,5\Rightarrow y=24\) ]

[\(\dfrac{x}{\dfrac{16}{3}}=10,5\Rightarrow x=56\) ]

Vậy \(x+y+z=42+24+56=122\)