\(x-y=5\)
=> \(x^2-2xy+y^2=25\)
=>\(-2xy=25-\left(x^2+y^2\right)=25-15=10\)
=>xy=-5
\(x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)=5\cdot\left(15-5\right)=5\cdot10=50\)
Ta có :
\(x-y=15\)
\(\Rightarrow x^2+y^2-2xy=25\)
\(\Rightarrow15-2xy=25\)
\(\Rightarrow xy=-5\)
\(\Rightarrow-xy=5\)
Mặt khác : \(x^3-y^3\)
\(=\left(x-y\right)\left(x^2+y^2+xy\right)\)
\(=5\left(15+5\right)\)
\(=15.20\)
\(=100\)