Tứ giác ABCD có: \(\widehat{A}+\widehat{B}+\widehat{C}+\widehat{D}=360^0\text{ ( Tổng các góc tứ giác ) }\)
\(\Rightarrow\widehat{D}=360^o-\left(\widehat{A}+\widehat{B}+\widehat{C}\right)\)
\(\Rightarrow\widehat{D}=360^o-\left(90^o+40^o+70^o\right)\)
\(\Rightarrow\widehat{D}=360^o-200^o\)
\(\Rightarrow\widehat{D}=160^o\)
Vậy \(\widehat{D}=160^o\)