Tự vẽ hình.
a) Vì \(BC=3KB\Rightarrow\dfrac{KB}{BC}=\dfrac{1}{3}\Rightarrow\dfrac{KC}{BC}=\dfrac{2}{3}\)
Ta có \(\dfrac{\dfrac{BK}{BC}}{\dfrac{KC}{BC}}=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\Rightarrow\dfrac{BK}{KC}=\dfrac{1}{2}\) (1)
Vì \(AI=2ID\Rightarrow\dfrac{ID}{AI}=\dfrac{1}{2}\)
Xét tam giác DAC có IM // AC
=> \(\dfrac{ID}{AI}=\dfrac{DM}{MC}=\dfrac{1}{2}\) (2)
Từ (1),(2) => \(\dfrac{BK}{KC}=\dfrac{DM}{MC}\left(=\dfrac{1}{2}\right)\)
=> MK // BD (ĐL Ta-lét đảo)