Xét tứ giác ABCD ta có:
\(\widehat{C}+\widehat{D}=360^o-\widehat{A}-\widehat{B}=360^o-125^o-55^o=180^o\)
\(\Rightarrow\widehat{ODC}+\widehat{OCD}=\dfrac{\widehat{C}+\widehat{D}}{2}=\dfrac{180^o}{2}=90^o\)
Ta lại có:
\(\widehat{DOC}=180^o-\left(\widehat{ODC}+\widehat{OCD}\right)=180^o-90^o=90^o\)
Vậy....................
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