Ta có :
\(\widehat{A}+\widehat{B}+\widehat{C}+\widehat{D}=360^0\\ Vì:\widehat{A}=3\cdot\widehat{D}\\ \Leftrightarrow3\cdot\widehat{D}+\widehat{B}+\widehat{C}+\widehat{D}=360^0\\ Mà:\widehat{B}+\widehat{C}=240^0\\ \Rightarrow4\cdot\widehat{D}=360^0-240^0=120^0\\ \Leftrightarrow\widehat{D}=\dfrac{120^0}{4}=30^0\\ \Rightarrow\widehat{A}=30^0\cdot3=90^0\\ Vậy\widehat{A}=90^0\)