Ta có:
\(\widehat{A}=2\widehat{B}=2.2\widehat{C}=4.3\widehat{D}=12\widehat{D}\)
\(\widehat{B}=2\widehat{C}=2.3\widehat{D}=6\widehat{D}\)
Ta có:
\(\widehat{A}+\widehat{B}+\widehat{C}+\widehat{D}=360^o\)
\(12\widehat{D}+6\widehat{D}+3\widehat{D}+\widehat{D}=360^o\)
\(22\widehat{D}=360^o\)
\(\widehat{D}=\dfrac{180}{11}^o\)