Có\(\frac{2x-3y}{6}=\frac{2x+3y}{8}\)
\(\Rightarrow\) \(8\left(2x-3y\right)=6\left(2x+3y\right)\)
\(\Rightarrow16x-24y=12x+18y\)
\(\Rightarrow16x-12x=24y+18y\)
\(\Rightarrow4x=42y\)
\(\Rightarrow\frac{x}{y}=\frac{42}{4}\)
Vậy \(\frac{x}{y}=\frac{42}{4}\)
\(\frac{2x-3y}{6}=\frac{2x+3y}{8}.\)
\(\Rightarrow\left(2x-3y\right).8=\left(2x+3y\right).6\)
\(\Rightarrow16x-24y=12x+18y\)
\(\Rightarrow16x-12x=18y+24y\)
\(\Rightarrow4x=42y\)
\(\Rightarrow\frac{x}{y}=\frac{42}{4}\)
\(\Rightarrow\frac{x}{y}=\frac{21}{2}.\)
Vậy \(\frac{x}{y}=\frac{21}{2}.\)
Chúc bạn học tốt!
