\(\dfrac{3a-b}{a+b}=\dfrac{3}{4}\)
\(\Rightarrow3\left(a+b\right)=4\left(3a-b\right)\)
\(\Rightarrow3\left(a+b\right)-4\left(3a-b\right)=0\)
\(\Rightarrow\left(3a+3b\right)-\left(12a-4b\right)=0\)
\(\Rightarrow3a+3b-12a+4b=0\)
\(\Rightarrow-9a+7b=0\)
\(\Rightarrow-9a=-7b\)
\(\Rightarrow\dfrac{a}{b}=\dfrac{-7}{-9}\)
\(\Rightarrow\dfrac{a}{b}=\dfrac{7}{9}\)
Vậy giá trị tỉ số \(\dfrac{a}{b}=\dfrac{7}{9}\)
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