b: \(\widehat{ACE}+\widehat{ACB}=90^0\)
mà \(\widehat{CAE}=180^0-90^0-\widehat{C}=90^0-\widehat{ACB}\)
nên \(\widehat{CAE}=\widehat{ACE}\)
hay ΔAEC cân tại E
a: \(\widehat{A}+\widehat{C}=180^0-30^0=150^0\)
\(\Leftrightarrow2\cdot\widehat{C}+90^0=150^0\)
\(\Leftrightarrow\widehat{C}=30^0\)
\(\Leftrightarrow\widehat{A}=120^0\)