Vì ABC cân tại A
\(\Rightarrow\widehat{B}=\widehat{C}\)
Xét tam giác ABC có:
\(\widehat{A}+\widehat{B}+\widehat{C}=180^o\left(định.lí\right)\)
\(\Rightarrow2\widehat{B}+\widehat{B}+\widehat{B}=180^o\\ \Rightarrow4\widehat{B}=180^o\\ \Rightarrow\widehat{B}=180^o:4\\ \Rightarrow\widehat{B}=45^o\\ \Rightarrow\widehat{C}=\widehat{B}=45^o\\ \Rightarrow\widehat{A}=2\widehat{B}=2.45^o=90^o\)