Xét tg ABC có \(\widehat{A}+\widehat{B}+\widehat{C}=180^0\Rightarrow\widehat{B}+\widehat{C}=180^0-70^0=110^0\)
Mà \(\widehat{B}-\widehat{C}=10^0\Rightarrow\left\{{}\begin{matrix}\widehat{B}=\left(110^0+10^0\right):2=60^0\\\widehat{C}=60^0-10^0=50^0\end{matrix}\right.\)
Ai trl đc luôn trong hôm nay thì mik cảm ơn trc nha