\(n_{CH_4}=\frac{V_{CH_4}}{22,4}=\frac{2,24}{22,4}=0,1\left(mol\right)\)
\(CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\)
\(0,1\) \(0,2\) \(0,1\) \(0,2\left(mol\right)\)
a) \(V_{CO_2}=n_{CO_2}.22,4=0,1.22,4=2,24\left(l\right)\)
b) \(V_{CO_2}=\frac{1}{5}.V_{kk}\Rightarrow V_{kk}=5.V_{CO_2}=5.2,24=11,2\left(l\right)\)