Để pt có 1 nghiệm \(x=-2\)
\(\Rightarrow-8+4-2m-4=0\Rightarrow m=-4\)
b/ Khi \(m=-4\)
\(\Leftrightarrow x^3+x^2-4x-4=0\)
\(\Leftrightarrow x^2\left(x+1\right)-4\left(x+1\right)=0\)
\(\Leftrightarrow\left(x^2-4\right)\left(x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=-1\\x=2\end{matrix}\right.\)