a) \(ĐKXĐ:\left\{{}\begin{matrix}x\ne3\\x\ne-1\end{matrix}\right.\)
b) \(P=\dfrac{2x^2+2x}{x^2-2x-3}=\dfrac{2x\left(x+1\right)}{\left(x+1\right)\left(x-3\right)}=\dfrac{2x}{x-3}\)
Để P = -1
<=> \(\dfrac{2x}{x-3}=-1\)
<=> \(2x=3-x\)
<=> 3x = 3
<=> x = 1 (tm)
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