\(\dfrac{a-x}{b-y}=\dfrac{a}{b}\)
\(\Rightarrow\left(a-x\right).b=\left(b-y\right).a\)
\(\Rightarrow ab-xb=ba-ya\)
\(\Rightarrow xb=ya\)
\(\Rightarrow\dfrac{a}{b}=\dfrac{x}{y}\) (đpcm)
Tìm số nguyên x, y biết:
a, \(\dfrac{-1}{5}\)≤ \(\dfrac{x}{8}\)≤ \(\dfrac{1}{4}\)
b, \(\dfrac{4}{x-6}\)= \(\dfrac{y}{24}\)= \(\dfrac{-12}{18}\)
c, \(\dfrac{x+46}{20}\)=x \(\dfrac{2}{5}\)
a, \(\dfrac{x-2}{15}+\dfrac{x-3}{14}+\dfrac{x-4}{13}+\dfrac{x-5}{12}=4\)
b, \(\dfrac{x+1}{19}+\dfrac{x+2}{18}+\dfrac{x+3}{17}+...+\dfrac{x+18}{2}+18=0\)
Cảm ơn khi đã giúp mình
a) \(\dfrac{1}{2.3}x+\dfrac{1}{3.4}x+\dfrac{1}{4.5}x+....+\dfrac{1}{49.50}x=1\)
b) \(\dfrac{1}{5}+\dfrac{2}{11}< \dfrac{x}{55}< \dfrac{2}{5}+\dfrac{1}{55}\)
a) a và b\(\in Z\) ; b > 0. Hãy so sánh
\(\dfrac{a}{b}\) và \(\dfrac{a+1}{b+1}\)
b) Áp dụng kết quả trên hãy so sánh:
\(\dfrac{2}{7}\) và \(\dfrac{3}{8}\) ; \(\dfrac{-17}{15}\) và \(\dfrac{-16}{26}\) ; \(\dfrac{31}{19}\) và \(\dfrac{32}{20}\)
Tìm x
a) \(\left[\left(6\dfrac{3}{7}-\dfrac{0,75.x-2}{0,35}\right).2,8+1,75\right]:0,05=2,35\)
b) \(\dfrac{3}{5}-\dfrac{2}{7}< \dfrac{2}{3}.x+\dfrac{3}{4}< \dfrac{1}{2}+\dfrac{7}{9}\)
a) \(7,5:\left(9-6\dfrac{13}{21}\right)=2\dfrac{13}{25}\) (câu này tính)
b) \(\dfrac{\left(1,16-x\right).5,25}{\left(10\dfrac{5}{9}-7\dfrac{1}{4}\right).2\dfrac{2}{17}}=75\%\)
c) \(\left(\dfrac{1}{1.3}+\dfrac{1}{3.5}+...+\dfrac{1}{19.21}\right).420-\left[0,4.\left(7,5-2,5x\right)\right]:0,25=212\)
tìm x biết
a, ( 3\(\dfrac{1}{3}\) - x) 1\(\dfrac{1}{6}\) = \(\dfrac{7}{24}\) b, ( 4,5 - 2x ) : \(\dfrac{3}{4}\) = 1\(\dfrac{1}{3}\)
Cho A= \(\dfrac{1}{4^2}+\dfrac{1}{6^2}+\dfrac{1}{8^2}+\dfrac{1}{10^2}+...+\dfrac{1}{160^2}\)
Chứng minh: \(\dfrac{1}{8}< A< \dfrac{3}{16}\)
Thực hiện phép tính( tính nhanh nếu có thể)
a, \(\left(-\dfrac{1}{2}\right)^2.\dfrac{7}{4}:\left(\dfrac{5}{8}-1\dfrac{3}{16}\right)\)
b, \(17\dfrac{6}{11}.\dfrac{4}{27}-8\dfrac{6}{11}:\dfrac{27}{4}+350\%\)
