Question

tìm x biết

a, ( 3\(\dfrac{1}{3}\) - x) 1\(\dfrac{1}{6}\) = \(\dfrac{7}{24}\) b, ( 4,5 - 2x ) : \(\dfrac{3}{4}\) = 1\(\dfrac{1}{3}\)

Answer 1

a) \(\left(3\dfrac{1}{3}-x\right)1\dfrac{1}{6}=\dfrac{7}{24}\)

\(\Leftrightarrow\left(\dfrac{10}{3}-x\right)\dfrac{7}{6}=\dfrac{7}{24}\)

\(\Leftrightarrow\dfrac{10}{3}-x=\dfrac{7}{24}:\dfrac{7}{6}\)

\(\Leftrightarrow\dfrac{10}{3}-x=\dfrac{1}{4}\)

\(\Leftrightarrow x=\dfrac{10}{3}-\dfrac{1}{4}\)

\(\Leftrightarrow x=\dfrac{37}{12}\).

b) \(\left(4,5-2x\right):\dfrac{3}{4}=1\dfrac{1}{3}\)

\(\Leftrightarrow\left(4,5-2x\right):\dfrac{3}{4}=\dfrac{4}{3}\)

\(\Leftrightarrow4,5-2x=\dfrac{4}{3}.\dfrac{3}{4}\)

\(\Leftrightarrow4,5-2x=1\)

\(\Leftrightarrow2x=4,5-1\)

\(\Leftrightarrow2x=3,5\)

\(\Leftrightarrow x=\dfrac{35}{2}\).