a: Để A là phân số thì n+3<>0
hay n<>-3
b: Để A là số nguyên thì \(n-2⋮n+3\)
\(\Leftrightarrow n+3\inƯ\left(-5\right)\)
\(\Leftrightarrow n+3\in\left\{1;-1;5;-5\right\}\)
hay \(n\in\left\{-2;-4;2;-8\right\}\)
bai 1
cho bieu thuc A = 5/n+1 voi N THUOC Z
a, de A la phan so thi n co dieu kien gi ?
b , tim tat ca cac gia tri nguyen cua n de gia tri A la 1 so nguyen ?
bai 2
cho bieu thuc M = 6/n-3 voi n thuoc Z .Co bao nhieu gia tri cua n de :
a, M ko phai la phan so
b , M la phan so va cp gia tri nguyen ?
bai 3 viet tap hop cacs so nguyen sao cho :
-12/4 < x <6/3
cho phan so n+9 / n-6 ( n thuoc N , n>6 )
tim n de n + 9 / n- 6 la toi gian
tim cac gia tri nguyen cua n de phan so A=3.n+2/n-1 co gia tri la so nguyen
tim phan so duong a/b nho nhat(a,b thuoc n *) sao cho khi nhan phan so do voi 24/5 va 16/3 deu duoc tich la so tu nhien
Cac ban giup minh nha, mai minh phai di hoc rui!!!
tim n de phan so sau la toi gian :
a, \(\dfrac{-3}{5-n}\) b,\(\dfrac{3n+2}{5n+3}\)
Voi gia tri nao cua x thuoc Z cac phan so sau co gia tri la 1 so nguyen
d, D=\(\dfrac{x^2-1}{x+1}\) e, E=\(\dfrac{n+2}{n-5}\)
voi gia tri nao cua x thuoc Z cac phan so sau co gia tri la 1 so nguyen
d.D= \(\dfrac{x^2-1}{x+1}\)
chung minh cac ps sau day la toi gian
b, \(\dfrac{n-1}{n-2}\)
A, Tim so tu nhien y de phan so 12/y co gia tri = 4
B, tim so tu nhien a de 3 phan so 21/a ; 22/a-1 ; 24/a+1 deu la so nguyen
chung minh cac phan so sau day la toi gian :
a, \(\dfrac{n+4}{n+3}\) b, \(\dfrac{n-1}{n-2}\)
