\(P=\dfrac{x}{\sqrt{x}-5}=\dfrac{x-25}{\sqrt{x}-5}+\dfrac{25}{\sqrt{x}-5}=\sqrt{x}+5+\dfrac{25}{\sqrt{x}-5}=\left(\sqrt{x}-5+\dfrac{25}{\sqrt{x}-5}\right)+10\)
Áp dụng BĐT AM-GM có;
\(\sqrt{x}-5+\dfrac{25}{\sqrt{x}-5}\ge10\)
\(\Rightarrow P\ge10+10=20\)
Dấu "=" xảy ra khi\(\sqrt{x}-5=\dfrac{25}{\sqrt{x}-5}\)\(\Leftrightarrow x=100\)(tm)
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