Question

Cho \(M=\left(\frac{\sqrt{x}}{x-4}+\frac{1}{\sqrt{x}-2}\right):\frac{2}{\sqrt{x}-2}\) . So sánh M và \(M^2\)

Cho \(M=\left(\frac{\sqrt{x}}{x-4}+\frac{1}{\sqrt{x}-2}\right):\frac{2}{\sqrt{x}-2}\) . So sánh M và \(\sqrt{M}\)

Answer 1

M=\(\left(\frac{\sqrt{x}}{x-4}+\frac{1}{\sqrt{x}-2}\right):\frac{2}{\sqrt{x}-2}\)

\(=\left(\frac{\sqrt{x}+\sqrt{x}+2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\right).\frac{\sqrt{x}-2}{2}\)

=\(\frac{2\sqrt{x}+2}{\sqrt{x}+2}.\frac{1}{2}\)

=\(\frac{\sqrt{x}+1}{\sqrt{x}+2}\)

So sánh

M<M²

M>\(\sqrt{M}\)

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