\(R_{tđ}=\dfrac{R_1.R_2}{R_1+R_2}=\dfrac{12.28}{12+28}=8,4\left(\Omega\right)\)
Do mắc nối tiếp nên \(I=I_1=1,8A\)
Do mắc song song nên \(U=U_1=U_2=I_1.R_1=1,8.12=21,6\left(V\right)\)
\(I_2=\dfrac{U_2}{R_2}=\dfrac{21,6}{28}=\dfrac{27}{35}\left(A\right)\)