Na2O + H2SO4 --> Na2SO4 + H2O
nNa2SO4 = 0,02 --> mNa2O = 1,24 gam
PTHH: Na2O+H2SO4\(\rightarrow\)Na2SO4 +H2O
\(n_{Na_2SO_4}=\frac{2,84}{142}=0,02\left(mol\right)\)
Theo PT: \(n_{Na_2O}=n_{Na_2SO_4}=0,02\left(mol\right)\)
\(\Rightarrow m_{Na_2O}=0,02.62=1,24\left(g\right)\)