a)
\(Ca+2H_2O\rightarrow Ca\left(OH\right)_2+H_2\left(1\right)\)
\(CaO+H_2O\rightarrow Ca\left(OH\right)_2\left(2\right)\)
b)
\(n_{H2}=\frac{3,36}{22,4}=0,15\left(mol\right)\)
\(\Rightarrow n_{Ca}=n_{H2}=0,15\left(mol\right)\)
\(\Rightarrow m_{Ca}=0,15.40=6\left(g\right)\)
\(\Rightarrow m_{CaO}=12-6=6\left(g\right)\)
c)
\(n_{CaO}=\frac{6}{40+16}=0,11\left(mol\right)\)
\(\Rightarrow n_{Ca\left(OH\right)2}=n_{CaO}=0,11\left(mol\right)\)
Mà \(n_{Ca\left(OH\right)2\left(1\right)}=n_{H2}=0,15\left(mol\right)\)
\(\Rightarrow n_{Ca\left(OH\right)_2}=n_{Ca\left(OH\right)2\left(1\right)}+n_{Ca\left(OH\right)2\left(2\right)}=0,26\left(mol\right)\)
\(\Rightarrow m_{Ca\left(OH\right)2}=0,26.\left[40+\left(1+16\right).2\right]=19,24\left(g\right)\)
