Xét \(\Delta BMF\) và \(\Delta CME\) có:
\(BM=MC\)
\(\widehat{BMF}=\widehat{CME}\left(dd\right),\widehat{MBF}=\widehat{MCE}\left(SLT\right)\)
\(\Rightarrow\Delta BMF=\Delta CME\)( g-c-g)
\(\Rightarrow S_{BMF}=S_{CME}\)(1)
\(\Leftrightarrow S_{BMF}+S_{ABMED}=S_{CME}+S_{ABMED}\)
\(\Leftrightarrow S_{ABCD}=S_{ADEF}\)
Lại có: (1)\(\Leftrightarrow S_{BMF}+S_{ABME}=S_{CME}+S_{ABME}\)
\(\Rightarrow S_{AEF}=S_{ADE}=S_{ABCE}=\frac{1}{2}S_{ADEF}=\frac{1}{2}S_{ABCD}\)
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