Ta có: \(y=f\left(x\right)=2x-3\)
\(f\left(x\right)=0\Rightarrow2x-3=0\Rightarrow x=\dfrac{3}{2}\)
\(f\left(x\right)=1\Rightarrow2x-3=1\Rightarrow x=2\)
\(f\left(x\right)=-\dfrac{3}{2}\Rightarrow2x-3=-\dfrac{3}{2}\Rightarrow x=\dfrac{3}{4}\)
\(f\left(x\right)=2022\Rightarrow2x-3=2022\Rightarrow x=\dfrac{2025}{2}\)