Ta có \(\widehat{AOB}+\widehat{BOC}=180^0\)(kề bù )
\(\Rightarrow2\widehat{BOC}+\widehat{BOC}=180^0\)
\(\Rightarrow3\widehat{BOC}=180^0\)
\(\Rightarrow\widehat{BOC}=60^0\)
\(\widehat{AOB} + \widehat{BOC} = 180^0\)
\(\widehat{AOB} = 2\widehat{BOC}\) (gt)
\(\Rightarrow\)\(\widehat{BOC} = 60^0\)
\(\widehat{AOB} = 120^0\)