Do \(\Delta ABC=\Delta HIK\)
=> AB = HI = 2cm;
\(\widehat{B}=\widehat{I}=40^o\);
\(BC=IK=4cm\)
\(\Delta\)ABC= \(\Delta\)HIK
Suy ra: AB=HI=2cm, BC=IK=6cm, \(\widehat{I}=\widehat{B}=40^0\)
Do tam giác ABC= tam giác HIK
Suy ra:AB= HI= 2 cm
góc B = góc I=40 độ
BC=IK= 4cm