Question

Cho D=\(\dfrac{2^{10}.3^8-2^8.3^9.4}{2^{10}.3^6+2^{16}.3^9}\)

Hãy tính D

Answer 1

\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^6+2^{16}\cdot3^9}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^6\left(1+2^6\cdot3^3\right)}=\dfrac{3^2\cdot\left(-2\right)}{1+64\cdot27}=\dfrac{-18}{1729}\)