\(C=\left(3+3^2+3^3+3^4\right)+\left(3^5+3^6+3^7+3^8\right)+...+\left(3^{97}+3^{98}+3^{99}+3^{100}\right)\)
\(C=3\left(1+3+3^2+3^3\right)+3^5\left(1+3+3^2+3^3\right)+...+3^{97}\left(1+3+3^2+3^3\right)\)
\(C=3.40+3^5.40+...+3^{97}.40\)
\(C=40\left(3+3^5+...+3^{97}\right)⋮40\) (đpcm)