\(C=\dfrac{1}{3}+\dfrac{1}{3^2}+....+\dfrac{1}{3^{20}}\\ \Rightarrow3.C=1+\dfrac{1}{3}+...+\dfrac{1}{3^{19}}\\ \Rightarrow3.C-C=\left(1+\dfrac{1}{3}+...+\dfrac{1}{3^{19}}\right)-\left(\dfrac{1}{3}+...+\dfrac{1}{3^{20}}\right)\\ =1-\dfrac{1}{3^{20}}< 1\\ \Rightarrow2C< 1\\ \Rightarrow C< \dfrac{1}{2}\)