\(a,P=\left(\frac{x}{x^2-4}+\frac{2}{2-x}+\frac{1}{x+2}\right):\frac{1}{x+2}\left(x\ne2;x\ne-2\right)\)
\(=\left(\frac{x-2\left(x+2\right)+x-2}{\left(x-2\right)\left(x+2\right)}\right).\left(x+2\right)\)
\(=\frac{x-2x-4+x-2}{x-2}\)
\(=\frac{-6}{x-2}\)
b, Để P nhận giá trị nguyên dương thì \(\frac{-6}{x-2}\) nhận giá trị nguyên dương
\(\Leftrightarrow x-2\inƯ\left(6\right)=\left\{1;2;3;6\right\}\)
| x-2 | 1 | 2 | 3 | 6 |
| x | 3(t/m) | 4(t/m) | 5(t/m) | 8(t/m |