\(F=\left(\frac{3+\sqrt{1-x^2}}{\sqrt{1+x}}\right).\left(\frac{\sqrt{1-x^2}}{3+\sqrt{1-x^2}}\right)=\frac{\sqrt{1-x^2}}{\sqrt{1+x}}=\sqrt{1-x}\)
\(x=4\sqrt{2}-5\Rightarrow F=\sqrt{1-\left(4\sqrt{2}-5\right)}=\sqrt{6-4\sqrt{2}}=\sqrt{\left(2-\sqrt{2}\right)^2}=2-\sqrt{2}\)