Thay A = 5 ta có:
\(\dfrac{\sqrt{x}+1}{\sqrt{x}-1}=5\)
\(\Rightarrow5\left(\sqrt{x}-1\right)=\sqrt{x}+1\)
\(\Rightarrow5.\sqrt{x}-5=\sqrt{x}+1\)
\(\Rightarrow4.\sqrt{x}=6\)
\(\Rightarrow\sqrt{x}=\dfrac{3}{2}\)
\(\Rightarrow x=\dfrac{9}{4}\)
Vậy \(x=\dfrac{9}{4}\)