Question

Cho biết \(\sqrt{x^2-6x+13}\) - \(\sqrt{x^2-6x+10}\)

Tính \(\sqrt{x^2-6x+13}\) + \(\sqrt{x^2-6x+10}\)

Answer 1

Ta có :

\(\sqrt{x^2-6x+13}-\sqrt{x^2-6x+10}\)

=\(\sqrt{x^2-2.3.x+3^2+4}-\sqrt{x^2-2.3.x+3^2+1}\)

=\(\sqrt{\left(x-3\right)^2+2^2}-\sqrt{\left(x-3\right)^2+1^2}\)

Answer 2

Ta có :

\(\sqrt{x^2-6x+13}+\sqrt{x^2-6x+10}\)

\(=\sqrt{x^2-6x+9+4}+\sqrt{x^2-6x+9+1}\)

\(=\sqrt{\left(x-3\right)^2+2^2}+\sqrt{\left(x-3\right)^2+1}\)

Answer 3

đề bài thiếu rồi bạn ơi