a)
\(\dfrac{2\left(x+1\right)}{3}-2\ge\dfrac{x-2}{2}\)
\(\Leftrightarrow\dfrac{2\left(x+1\right)\cdot2}{6}-\dfrac{6}{6}-\dfrac{3\left(x-2\right)}{6}\ge0\)
\(\Leftrightarrow\dfrac{4x+4-6-3x+6}{6}\ge0\)
\(\Leftrightarrow\dfrac{x+4}{6}\ge0\)
\(\Leftrightarrow x+4\ge0\Leftrightarrow x\ge-4\)
b) Tự biểu diễn