Bài 9: Căn bậc ba
Các câu hỏi tương tự
Tính giá trị các biểu thức:
a)( \(\frac{1}{2}\sqrt[3]{9}-2\sqrt[3]{3}+3\sqrt[3]{\frac{1}{3}}\)) : \(2\sqrt[3]{\frac{1}{3}}\)
b)\(\left(12\sqrt[3]{2}+\sqrt[3]{16}-2\sqrt[3]{2}\right)\left(5\sqrt[3]{4}-3\sqrt[3]{\frac{1}{2}}\right)\)
Giải các phương trình sau:
a)\(\sqrt{1-2x}+\sqrt{1+2x}=2-x^2\)
b)\(\sqrt{2x-\frac{3}{x}}+\sqrt{\frac{6}{x}-2x}=1+\frac{3}{2x}\)
c)\(\sqrt[3]{x+1}=x^3-15x^2+75x-131\)
d)\(x^2-x-2\sqrt{1+16x}=2\)
e)\(7x^2+7x=\sqrt{\frac{4x+9}{28}}\)với x>0
Giải PT.
a)\(\sqrt[3]{x+4}-\sqrt[3]{x-6}=1\)
b)\(\sqrt[3]{x^2-8\sqrt[3]{x}}=20\)
c)\(\frac{x\sqrt[3]{x}-1}{\sqrt[3]{x^2-1}}-\frac{\sqrt[3]{x^2-1}}{\sqrt[3]{x}}=4\)
\(A=\left(\frac{3x-3\sqrt{x}-3}{x+\sqrt{x}-2}+\frac{1}{\sqrt{x}-1}-\frac{1}{\sqrt{x}+2}\right):\frac{1}{\sqrt{x}+2}\) với \(x\ge0;x\ne9\)
Rút gọn các biểu thức:
a) A frac{sqrt[3]{135}}{sqrt[3]{5}}-sqrt[3]{54}sqrt[3]{4}
b) B left(frac{1}{2}sqrt[3]{2}-frac{1}{4}sqrt[3]{16}right).sqrt[3]{4}
c) C sqrt[3]{left(sqrt{2}+1right)left(3+2sqrt{2}right)}
d) D sqrt[3]{3+3sqrt[3]{2}+3sqrt[3]{4}}
e) E sqrt[3]{2+sqrt{5}}+sqrt[3]{2-sqrt{5}}
Đọc tiếp
Rút gọn các biểu thức:
a) A= \(\frac{\sqrt[3]{135}}{\sqrt[3]{5}}-\sqrt[3]{54}\sqrt[3]{4}\)
b) B= \(\left(\frac{1}{2}\sqrt[3]{2}-\frac{1}{4}\sqrt[3]{16}\right).\sqrt[3]{4}\)
c) C= \(\sqrt[3]{\left(\sqrt{2}+1\right)\left(3+2\sqrt{2}\right)}\)
d) D= \(\sqrt[3]{3+3\sqrt[3]{2}+3\sqrt[3]{4}}\)
e) E= \(\sqrt[3]{2+\sqrt{5}}+\sqrt[3]{2-\sqrt{5}}\)
Cho a, b, c, x, y, z thoả mãn: x + y + z = 1 và \(\dfrac{a}{x^3}=\dfrac{b}{y^3}=\dfrac{c}{z^3}\). Chứng minh rằng: \(\sqrt[3]{\dfrac{a}{x^2}+\dfrac{b}{y^2}+\dfrac{c}{z^2}}=\sqrt[3]{a}+\sqrt[3]{b}+\sqrt[3]{c}\)
thực hiện phép tính
a)\(\left(\frac{1}{2}\sqrt[3]{9}-2\sqrt[3]{3}+3\sqrt[3]{\frac{1}{3}}\right):2\sqrt[3]{\frac{1}{3}}\)
b)\(\left(\sqrt[3]{9}-\sqrt[3]{6}+\sqrt[3]{4}\right)\left(\sqrt[3]{3}+\sqrt[3]{2}\right)\)
thực hiện phép tính
a)\(\left(\frac{1}{2}\sqrt[3]{9}-2\sqrt[3]{3}+3\sqrt[3]{\frac{1}{3}}\right):2\sqrt[3]{\frac{1}{3}}\)
b)\(\left(\sqrt[3]{9}+\sqrt[3]{6}-\sqrt[3]{4}\right)\left(\sqrt[3]{3}+\sqrt[3]{2}\right)\)
\(\sqrt[3]{2+10\sqrt{\frac{1}{27}}}\) + \(\sqrt[3]{2+10\sqrt{\frac{1}{27}}}\)
E = \(\sqrt[3]{4+\frac{5}{3}\sqrt{\frac{31}{3}}}\)+ \(\sqrt[3]{4-\frac{5}{3}\sqrt{\frac{31}{3}}}\)