Question

Cho A=\(\dfrac{3}{4}\).\(\dfrac{8}{9}.\dfrac{15}{16}.\dfrac{24}{25}....\dfrac{9800}{9801}\) và B=\(\dfrac{1.2+2.3+3.4+....+98.99}{98.99.100}\)

So sánh Avà B

Answer 1

A = \(\dfrac{3}{4}\).\(\dfrac{8}{9}\).\(\dfrac{15}{16}.\)\(\dfrac{24}{25}\)...\(\dfrac{9800}{9801}\)

A = \(\dfrac{1.3}{2.2}\).\(\dfrac{2.4}{3.3}\).\(\dfrac{3.5}{4.4}\)...\(\dfrac{98.100}{99.99}\)

A = \(\dfrac{1}{2}.\dfrac{100}{99}\)

A = \(\dfrac{50}{99}\) 

B = \(\dfrac{1.2+2.3+3.4+...+98.99}{98.99.100}\)

Đặt tử số là C Thì 

C = 1.2 + 2.3 + 3.4 +...+ 98.99

C = \(\dfrac{1}{3}\).(1.2.3 + 2.3.3 + 3.4.3 + ...+ 98.99.3)

C = \(\dfrac{1}{3}\).[1.2.3 + 2.3.(4-1) + 3.4.(5-2) +...+ 98.99.(100-97)]

C = \(\dfrac{1}{3}\).[1.2.3 -1.2.3+2.3.4- 2.3.4 + 2.4.5 - .... - 97.98.99 + 98.99.100]

C = \(\dfrac{1}{3}\).98.99.100

B = \(\dfrac{\dfrac{1}{3}.98.99.100}{98.99.100}\) 

B = \(\dfrac{1}{3}\) = \(\dfrac{33}{99}\) < \(\dfrac{50}{99}\) = A

Vậy B < A