\(VT=\left(a+\frac{1}{a}\right)^2+\left(b+\frac{1}{b}\right)^2+\left(c+\frac{1}{c}\right)^2\)
\(VT\ge\frac{1}{3}\left(a+\frac{1}{a}+b+\frac{1}{b}+c+\frac{1}{c}\right)^2=\frac{1}{3}\left(a+b+c+\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)^2\)
\(VT\ge\frac{1}{3}\left(a+b+c+\frac{9}{a+b+c}\right)^2=\frac{1}{3}\left(1+\frac{9}{1}\right)^2=\frac{100}{3}>33\)