Cách 1 :
Ta có :
VO2 = 0,2.22,4 = 4,48(l)
VSO3 = \(\dfrac{32}{80}.22,4=8,96\left(l\right)\)
VCO2 = \(\dfrac{1,8.10^{23}}{6.10^{23}}.22,4=6,72\left(l\right)\)
VA = VO2 + VSO3 + VCO2 = 4,48 + 8,96 + 6,72 = 20,16(l)
Cách 2 :
Ta có :
VA = (0,2 + \(\dfrac{32}{80}\) + \(\dfrac{1,8.10^{23}}{6.10^{23}}\) ) .22,4 = 20,16(l)