PTHH: Zn + 2HCl -> ZnCl2 + H2
-------0,06---0,12-------0,06----0,06--
PTHH: Zn(OH)2 + 2HCl -> ZnCl2 + 2H2O
----------0,07----------0,14-----0,07----0,07--
=> a = 0,06.65 + 0,07.99 = 10,83 (g)
mddspư = 10,83 + 100 - 0,06.2 = 110,71 (g)
=> C%ZnCl2 = (mct.100)/mdd = (17,68.100)/110,71 ≃ 15,97 %