a:ĐKXĐ: \(x\notin\left\{1;0\right\}\)
b: \(A=\dfrac{\left(x-1\right)^2}{x}\cdot\dfrac{x-1-x^2}{x-1}-\dfrac{6x+1}{x}\)
\(=\dfrac{\left(x-1\right)\left(-x^2+x-1\right)}{x}-\dfrac{6x+1}{x}\)
\(=\dfrac{-x^3+x^2-x+x^2-x+1-6x-1}{x}\)
\(=\dfrac{-x^3+2x^2-8x}{x}=-x^2-2x-8\)
c: \(A=-\left(x^2+2x+8\right)=-\left(x+1\right)^2-7\le-7\)
Dấu '=' xảy ra khi x=-1