\(B=4\left(a^3+b^3\right)-6\left(a^2+b^2\right)\\ B=4\left[\left(a+b\right)^3-3ab\left(a+b\right)\right]-6\left[\left(a+b\right)^2-2ab\right]\\ =4\left(a+b\right)^3-12ab\left(a+b\right)-6\left(a+b\right)^2+12ab\\ =4\cdot1^3-12ab-6\cdot1^2+12ab=4-6=-2\)
Vậy chọn B