\(n_{Zn}=\dfrac{m}{M}=\dfrac{6,5}{65}=0,1\left(mol\right)\\ PTHH:Zn+H_2SO_4->ZnSO_4+H_2\)
tỉ lệ 1 ; 1 ; 1 ; 1
n(mol) 0,1-->0,1--------->0,1--------->0,1
\(V_{H_2\left(dktc\right)}=n\cdot22,4=0,1\cdot22,4=2,24\left(l\right)\\ m_{H_2SO_4}=n\cdot M=0,1\cdot\left(2+32+16\cdot4\right)=9,8\left(g\right)\\ m_{ZnSO_4}=n\cdot M=0,1\cdot\left(65+32+16\cdot4\right)=16,1\left(g\right)\)
a, \(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\)
PT: \(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\)
____0,1____0,1________0,1____0,1 (mol)
\(\Rightarrow V_{H_2}=0,1.22,4=2,24\left(l\right)\)
b, \(m_{H_2SO_4}=0,1.98=9,8\left(g\right)\)
\(m_{ZnSO_4}=0,1.161=16,1\left(g\right)\)
\(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\)
\(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\)
0,1 0,1 0,1 0,1 ( mol )
\(V_{H_2}=0,1.22,4=2,24\left(l\right)\)
\(m_{H_2SO_4}=0,1.98=9,8\left(g\right)\)
\(m_{ZnSO_4}=0,1.161=16,1\left(g\right)\)
